Respuesta :

chewhiuyonowuwox
The answer is C.

∠STR = ∠SRQ = 90° (given) (A)
∠RST = ∠RSQ (common angle) (A)

By AA test for similarity,
∆STR is similar to ∆SRQ.
JeanaShupp

Answer:   C.  ΔSQR

Step-by-step explanation:

In [tex]\triangle{STR}[/tex] and [tex]\triangle{SQR}[/tex], we have

[tex]\angle{TSR}\cong\angle{OSR}\\\\\angle{STR}\cong\angle{QRS}=90^{\circ}[/tex]

By AA- similarity postulate , we get

[tex]\triangle{STR}\sim\triangle{SQR}[/tex]

  • AA-similarity postulate says that two triangles are said to be similar if they have two corresponding angles that are congruent or equal in measure.

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