Calculate freezing temperature of.5 M sodium chloride solution. Assume that the molality of each solution is .5 M

a. -.93 Celsius
b. -1.86 Celsius
c. -3.72 Celsius
d. -.538 Celsius

Respuesta :

Given,
Molality = .5M

We know, Kf = 1.86

Now,
Δ T = M x Kf
      = 1.86 * 0.5
      = 0.93 °C

Now,
Freezing point = Initial freezing point - Δ T
                     = 0°C - 0.93°C
                     = -0.93°C
So, the answer is A