5.
A 500g sample of an unknown metal releases 6.4 x 102 J as it
cools from 55.0 °C to 25.0 °C. What is the specific heat of the
sample?

Respuesta :

To find the specific heat of the unknown metal sample, you can use the formula: \( q = mcΔT \), where: - \( q \) is the heat energy absorbed or released, - \( m \) is the mass of the sample (500g in this case), - \( c \) is the specific heat capacity of the material (what we are trying to find), - \( ΔT \) is the change in temperature (55.0 °C - 25.0 °C = 30.0 °C). Given that the heat energy released is 6.4 x 10^2 J, you can substitute the values into the formula and solve for the specific heat capacity (\( c \)): \( 6.4 x 10^2 J = (500g) * c * 30.0°C \). First, convert the mass to kg by dividing by 1000 (500g = 0.5kg). Then, rearrange the formula to solve for \( c \): \( c = \frac{6.4 x 10^2 J}{(0.5kg * 30.0°C)} \). Calculate the specific heat capacity \( c \) using this equation to find the value.