contestada

y varies jointly as z and of the square of x and inversely as t and of the square root of w. When x=2, z=3, w=16, and t=3, then y=1. Find y when x=3, z=2, w=36 and t=1.

Respuesta :

The relationship given can be expressed as:

y = k * (z * x^2) / (t * √w)

Given that when x = 2, z = 3, w = 16, and t = 3, y = 1, we can use these values to find the constant k:

1 = k * (3 * 2^2) / (3 * √16)
1 = k * (3 * 4) / (3 * 4)
1 = k

So, k = 1.

Now, when x = 3, z = 2, w = 36, and t = 1, we can plug these values into the equation to find y:

y = 1 * (2 * 3^2) / (1 * √36)
y = (2 * 9) / (1 * 6)
y = 18 / 6
y = 3

So, when x = 3, z = 2, w = 36, and t = 1, y = 3.

Otras preguntas