The given expression represents the nth term (tn) of an arithmetic progression (A.P.) where each term is obtained by adding a constant difference (d) to the previous term.
In this case, the expression for the nth term (tn) is given by:
tn = 2n + 1
To find the A.P., we need to express each term in terms of n. We can do this by substituting the values of n = 1, 2, 3, ... into the given expression to find the corresponding terms.
For n = 1:
t1 = 2(1) + 1 = 3
For n = 2:
t2 = 2(2) + 1 = 5
For n = 3:
t3 = 2(3) + 1 = 7
Continuing this pattern, we find the following terms of the A.P.:
3, 5, 7, 9, ...
So, the arithmetic progression (A.P.) is 3, 5, 7, 9, ...
