If ray BD bisects angle CBE, ray BC is transparent to ray BA, angle CBD = (3x + 25) degrees, and angle DBE = (7x - 19) degrees, find angle ABD

If ray BD bisects angle CBE ray BC is transparent to ray BA angle CBD 3x 25 degrees and angle DBE 7x 19 degrees find angle ABD class=

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Answer:  The required measure of angle ABD is 148°.  

Step-by-step explanation:  Given that ray BD bisects angle CBE, ray BC is transparent to ray BA.

Also,

[tex]m\angle CBD=(3x+25)^\circ,~~m\angle DBE=(7x-19)^\circ,~~m\angle ABC=90^\circ.[/tex]

We are to find the measure of angle ABD.

Since ray BD bisects angle CBE, so we have

[tex]m\angle CBD=m\angle DBE\\\\\Rightarrow (3x+25)^\circ=(7x-19)^\circ\\\\\Rightarrow 3x+25=7x-19\\\\\Rightarrow 7x-3x=25+19\\\\\Rightarrow 4x=44\\\\\Rightarrow x=\dfrac{44}{4}\\\\\Rightarrow x=11.[/tex]

So, we get

[tex]m\angle CBD=(3\times11+25)^\circ=58^\circ.[/tex]

Therefore,

[tex]m\angle ABD=m\angle ABC+m\angle CBD=90^\circ+58^\circ=148^\circ.[/tex]

Thus, the required measure of angle ABD is 148°.