Answer:
3 × 10⁴
Explanation:
We are given two numbers, [tex]n_1=9\times 10^{-5}[/tex] and [tex]n_2=3\times 10^{-9}[/tex]
We have to divide n₁ by n₂. We know that,
[tex]\dfrac{10^n}{10^m}=10^{n-m}[/tex]
Here, n = -5 and m = -9
So on dividing we get :
[tex]\dfrac{9\times 10^{-5}}{3\times 10^{-9}}=3\times 10^{-5+9}=3\times 10^4[/tex]
Hence, on dividing n₁ by n₂ obtained number is 3 × 10⁴.
