Answer:
[tex]9.95gC_{6}H_{12}O_{2}[/tex]
Explanation:
The balanced reaction will be:
[tex]C_{4}H_{8}O_{2}+C_{2}H_{5}OH=C_{6}H_{12}O_{2}+H_{2}O[/tex]
The molecular weight of the ethyl butyrate is:
Atomic weight C = 12[tex]\frac{g}{mol}[/tex]
Atomic weight O = 16[tex]\frac{g}{mol}[/tex]
Atomic weight H = 1[tex]\frac{g}{mol}[/tex]
Molecular weight [tex]C_{6}H_{12}O_{2}[/tex] = (6*12)+(1*12)+(16*2)
Molecular weight [tex]C_{6}H_{12}O_{2}[/tex] = 116[tex]\frac{g}{mol}[/tex]
The molecular weight of the butanoic acid is:
Atomic weight C = 12[tex]\frac{g}{mol}[/tex]
Atomic weight O = 16[tex]\frac{g}{mol}[/tex]
Atomic weight H = 1[tex]\frac{g}{mol}[/tex]
Molecular weight [tex]C_{4}H_{8}O_{2}[/tex] = (4*12)+(1*8)+(16*2)
Molecular weight [tex]C_{4}H_{8}O_{2}[/tex] = 88[tex]\frac{g}{mol}[/tex]
Finding the mass using stoichiometry:
[tex]7.55gC_{4}H_{8}O_{2}*\frac{1molC_{4}H_{8}O_{2}}{88gC_{4}H_{8}O_{2}}*\frac{1molC_{6}H_{12}O_{2}}{1molC_{4}H_{8}O_{2}}*\frac{116gC_{6}H_{12}O_{2}}{1molC_{6}H_{12}O_{2}}=9.95gC_{6}H_{12}O_{2}[/tex]
