Answer:
Answer: The final velocity of the roller coaster is 58.04[tex]\frac{m}{s}[/tex]
Explanation:
Kinematics of the problem:
The The roller coaster moves with uniform accelerated movement moves with uniform accelerated movement, then, We use the acceleration equation for this type of movement:
[tex]v_{f} ^{2} =v_{i} ^{2} +2*a*d[/tex] Formula 1
[tex]v_{f}[/tex]: final speed
[tex]v_{i}[/tex]: initial speed=[tex]13\frac{m}{s}[/tex]
[tex]a=4\frac{m}{s^{2} }[/tex]
d=distance traveled by The roller coaster =400m
Final velocity calculating:
We replace known information in the formula 1:
[tex]v_{f} ^{2} =13^{2} +2*4*400[/tex]
[tex]v_{f} ^{2} =169+3200[/tex]
vf2=3369
[tex]v_{f} =\sqrt{3369}[/tex]
[tex]v_{f} =58.04 \frac{m}{s}[/tex]
Answer: The final velocity of the roller coaster is [tex]58.04\frac{m}{s}[/tex]
