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points a,b and c are collinear on AC, and AB:BC=3/4. A is located at (x,y), B is located at (4,1), and c is located at (12,5). what are the values of x and y?

Respuesta :

Answer:  The required values are  x = 2  and  y = 2.

Step-by-step explanation:  Given that the points A, B and C are collinear on AC and AB : BC = 3 : 4.

Also, A is located at (x, y), B is located at (4, 1) and C is located at (12,5).

We are to find the values of x and y.

We know that

the co-ordinates of a point that divides a line segment with endpoints (a, b) and (c, d) in the ratio m : n are given by

[tex]\left(\dfrac{mc+na}{m+n},\dfrac{md+nb}{m+n}\right).[/tex]

According to the given information, we get

[tex]4=\dfrac{3\times 12+4\times x}{3+4}\\\\\\\Rightarrow 4=\dfrac{36+4x}{7}\\\\\Rightarrow 36+4x=28\\\\\Rightarrow 4x=8\\\\\Rightarrow x=\dfrac{8}{4}\\\\\Rightarrow x=2[/tex]

and

[tex]1=\dfrac{3\times5+4\times y}{3+4}\\\\\\\Rightarrow 1=\dfrac{15+4y}{7}\\\\\Rightarrow 15+4y=7\\\\\Rightarrow 4y=8\\\\\Rightarrow y=\dfrac{8}{4}\\\\\Rightarrow y=2.[/tex]

Thus, the required values are  x = 2  and  y = 2.

Using line segments, it is found that:

  • The value of x is -2.
  • The value of y is -2.

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  • Point A is located at (x,y).
  • Point B is located at (4,1).
  • Point C is located at (12,5).
  • AB:BC=3/4 means that:

[tex]B - A = \frac{3}{4}(C - B)[/tex]

  • This is used to find the x and y-coordinates of A.

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  • The x-coordinate of A is x.
  • The x-coordinate of B is 4.
  • The x-coordinate of C is 12.

Thus:

[tex]B - A = \frac{3}{4}(C - B)[/tex]

[tex]4 - x = \frac{3}{4}(12 - 4)[/tex]

[tex]4 - x = 6[/tex]

[tex]x = -2[/tex]

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  • The y-coordinate of A is y.
  • The y-coordinate of B is 1.
  • The y-coordinate of C is 5.

Thus:

[tex]B - A = \frac{3}{4}(C - B)[/tex]

[tex]1 - y = \frac{3}{4}(5 - 1)[/tex]

[tex]1 - y = 3[/tex]

[tex]y = -2[/tex]

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