A rock falls off the edge of a cliff that is 145 m above the ground beneath it. For how long a time is the rock falling? Assume air resistance is negligible.
the initial velocity is zero the acceleration is 9.81m/s² due to gravity the displacement is 145m Therefore, the formula you use: d=vinitial*t + 1/2at² Since v initial is zero we can cancel out the first of the equation which as the product will come out to be 0. Therefore, t= √2d/a =√2(145)/(9.81) =5.4370...s or to proper sigdigs 5.44s Hope this helps!
