Answer:
Area = 18 in²
Step-by-step explanation:
The area of a triangle is half the product of its base and height:
[tex]\boxed{\begin{array}{l}\underline{\textsf{Area of a triangle}}\\\\A=\dfrac{1}{2}bh\\\\\textsf{where:}\\\phantom{ww}\bullet\; \textsf{$A$ is the area.}\\ \phantom{ww}\bullet\;\textsf{$b$ is the base.}\\ \phantom{ww}\bullet\;\textsf{$h$ is the height.}\end{array}}[/tex]
In this case:
Substitute the values of the base and height into the area formula, and solve for A:
[tex]\rm A=\dfrac{1}{2} \cdot 6\;in \cdot 6 \; in\\\\\\A=3\;in \cdot 6 \; in\\\\\\A=18\; in^2[/tex]
Therefore, the area of the given triangle is:
[tex]\LARGE\textsf{Area\;$=\boxed{18}$\;in$^2$}[/tex]
