Ostritch6444 Ostritch6444

26-08-2017
Physics

contestada

A small object carrying a charge of -3.00 nc is acted upon by a downward force of 30.0 nn when placed at a certain point in an electric field.

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meerkat18 meerkat18

05-09-2017

The working equation for this one is:

E = F/Q, where E is the strength of the electric field, F is the electric force and Q is the charge. Substituting the corresponding values, the strength of the electric field is equal to

E = -30 nN/-3 nC
E = 10 nN/nC

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