In major league baseball, the pitcher’s mound is 60 feet from the batter. If a pitcher throws a 95 mph fastball, how much time elapses from when the ball leaves the pitcher’s hand until the ball reaches the batter?

Respuesta :

Answer:

0.44 seconds

Explanation:

To calculate the time it takes for the ball to travel from the pitcher's hand to the batter, we can use this formula:

time = distance / speed

In this case, the distance is 60 feet, which is 18.29 meters. To convert this to meters, we can multiply by the factor 0.3048:

distance = 60 feet * 0.3048 meters/foot = 18.29 meters

The speed of the ball is 95 miles per hour, which is 152.89 kilometers per hour. To convert this to meters per second, we can multiply by the factor 0.277778:

speed = 95 miles/hour * 1.60934 kilometers/mile * 1000 meters/kilometer * 0.277778 hours/second = 42.47 meters/second

Now we can substitute these values into the formula to get:

time = 18.29 meters / 42.47 meters/second = 0.44 seconds

So, it takes 0.44 seconds for a 95 mph fastball to travel from the pitcher's hand to the batter.