The equation of a circle is (x - 4)² + (y + 3)² = 9. What are the coordinates of the center of this circle?
Responses

(-4, -3)
(-4, -3)

(4, 3)
(4, 3)

(4, -3)
(4, -3)

(-4, 3)
(-4, 3)

Respuesta :

Answer:

The coordinates of the center of this circle are (4,−3).

Step-by-step explanation:

The equation of a circle in the form (x − h)^2 + (y − k)^2 = r^2 represents a circle centered at the point (h , k) with a radius r.

In your equation (x − 4)^2 + ( y + 3)^2 = 9 , the center of the circle is at the point (h , k) = (4,−3). Therefore, the coordinates of the center of this circle are (4,−3).

msm555

Answer:

[tex] (4, -3) [/tex]

Step-by-step explanation:

The equation of a circle in the standard form is:

[tex] \Large\boxed{\boxed{(x - h)^2 + (y - k)^2 = r^2}} [/tex]

Where

  • [tex](h, k)[/tex] represents the coordinates of the center of the circle, and
  • [tex]r[/tex] represents the radius.

In the given equation:

[tex] (x - 4)^2 + (y + 3)^2 = 9 [/tex]

We can identify that [tex](h, k) = (4, -3)[/tex] by comparing the standard equation of the circle., as [tex](h, k)[/tex] are the coordinates of the center of the circle.

So, the correct coordinates of the center of this circle are [tex](4, -3)[/tex].

The correct response is:

[tex] (4, -3) [/tex]