Answer:
7.475 seconds pass before the object makes a splash
Explanation:
The time it takes for a dropped object to fall and hit the ground can be determined using the kinematic equation.
h=1/2gt^2
h is the height (in meters),
g is the acceleration due to gravity (approximately 9.8 m/s^2 ),
t is the time (in seconds).
h=274
g = 9.8m/s^2
Then rewrite the problem as:
[tex]T=\frac{2*h}{g}[/tex]
Plug in Values
[tex]T=\frac{2*274}{9.8}[/tex]
Solve
[tex]T= \sqrt{\frac{548}{9.8}}[/tex]
Calculate
[tex]T=\sqrt{55.918}[/tex]
T=7.475 seconds
Approximately 7.475 seconds pass before the object makes a splash.
