contestada

A car accelerates from rest to 48m/s in 6s. How far did it travel during this time period

Respuesta :

Answer:

Explanation:

a=(v-u)/t
is the equation- where:
v-final velocity
u-initial velocity
t-is time
and substituting values makes:
48=v-0 / 6
make V subject:
v= 48*6=288 m/s

next equation is v= d/t
d-distance
v-velocity
t-time

which is d = v * t = 288 * 6 = 1728m

Displacement = (velocity + Initial velcoity/2 )*t

0 is the i initial velocity ( u )
48 is the final velocity ( v )
time is 6 seconds
so
48-0 divide 2 = 24
24 x 6 = 144m

144m is how far the car travelled during 6 seconds with this acceleration