Answer: [tex]\sqrt{5}[/tex] which is choice C
Explanation
Focus on points D(0,9) and E(3,3)
Take 1/3 of each coordinate to get D'(0,3) and E'(1,1)
Let's find the distance between those two new points.
[tex](x_1,y_1) = (0,3) \text{ and } (x_2, y_2) = (1,1)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-1)^2 + (3-1)^2}\\\\d = \sqrt{(-1)^2 + (2)^2}\\\\d = \sqrt{1 + 4}\\\\d = \sqrt{5}\\\\d \approx 2.2361\\\\[/tex]
Segment D'E' is exactly [tex]\sqrt{5}[/tex] units long which approximates to about 2.2361 units.