[tex]\mathbb P(X=x)=\begin{cases}\dfrac{\binom{48}4\binom40}{\binom{52}4}\approx0.7187&\text{for }x=0\\\\\dfrac{\binom{48}3\binom41}{\binom{52}4}\approx0.2556&\text{for }x=1\\\\\dfrac{\binom{48}2\binom42}{\binom{52}4}\approx0.0250&\text{for }x=2\\\\\dfrac{\binom{48}1\binom43}{\binom{52}4}\approx0.0007&\text{for }x=3\\\\\dfrac{\binom{48}0\binom44}{\binom{52}4}\approx0.0000037&\text{for }x=4\\\\0&\text{otherwise}\end{cases}[/tex]
