Respuesta :

[tex]\bf \begin{array}{rllll} (12&,&16)\\ \uparrow &&\uparrow \\ x&&y \end{array}\quad tan(\theta)=\cfrac{y}{x}\qquad \qquad tan(\theta )=\cfrac{16}{12}\implies tan(\theta )=\cfrac{4}{3}[/tex]

Answer:

tan(θ)=4/3

Step-by-step explanation:

Since opposite leg of the reference triangle equals 16 and the adjacent leg equals 12, tan(θ)=16/12 simplified to tan(θ)=4/3.

Ver imagen lavenderamour

Otras preguntas