Sodium hydrogen carbonate nahco3 , also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid hcl , which the stomach secretes to help digest food. drinking a glass of water containing dissolved nahco3 neutralizes excess hcl through this reaction: hcl (aq) nahco3 (aq) â nacl (aq) h2o (l) co2 (g) the co2 gas produced is what makes you burp after drinking the solution. suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 250.ml of a 0.076 m hcl solution. what mass of nahco3 would he need to ingest to neutralize this much hcl

Molarity = number pf moles / volume in liters.
Number of moles of HCl needed to be neutralized = molarity * volume = 0.076 * 250/1000 = 0.019 moles.
HCl + NaHCO3 = NaCl + H2O = CO2
1 mole of HCl reacts with 1 mole of NaHCO3
1 mole of NaHCO3 = 23 + 1 + 14 + 3*16 = 86 grams.
1 mole HCl reacts with 86 g
0.019 moles reacts with x g
x = 0.019 * 86 = 1.634 grams

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IthaloAbreu IthaloAbreu · Answer 2 · 2019-12-18T18:49:14+01:00

Answer:

1.596 g

Explanation:

The neutralization reaction is:

NaHCO₃ + HCl → NaCl + H₂O + CO₂

The number of moles of the acid in stomach is the volume (250.0 mL = 0.250 L) multiplied by the molar concentration (0.076 M):

n = 0.250 * 0.076 = 0.019 mol of HCl

By the stoichiometry of the reaction, 1 mol of NaHCO₃ is needed to neutralize 1 mol of HCl, so it'll be necessary 0.019 mol of sodium bicarbonate.

The molar mass of NaHCO₃ is 84 g/mol, thus the mass of it is:

m = number of moles * molar mass

m = 0.019 * 84

m = 1.596 g