Respuesta :

mathmate
If we define "n choose r" as C(n,r)=n!/(r!(n-r)!)
where C(n,r) represents the number of ways (order not important) we can choose r objects out of n, then

Number of ways to choose teachers = 10 choose 2 = C(10,2), and
number of ways to choose students = 41 choose 2 = C(41,2)

So the number of different committees 
= C(10,2)*C(41,2)
= 45*820
= 36900 
konrad509
[tex]10C2\cdot41C2=\dfrac{10!}{2!8!}\cdot\dfrac{41!}{2!39!}=\dfrac{9\cdot10}{2}\cdot\dfrac{40\cdot41}{2}=36,900[/tex]

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