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In triangle​ abc, the measure of angle b is 29 degrees° more than three times the measure of angle

a. the measure of angle c is 61 degrees° more than the measure of angle

a. find the measure of each angle.

Respuesta :

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∠a = x
∠b = 3x + 29
∠c = x + 61

x + 3x + 29 + x + 61 = 180
5x = 180 - 29 - 61
5x = 90
x = 90/5
x = 18°  ← ∠a

∠b = 3x + 29 = 3*18 + 29 = 83°

∠c = x + 61 = 18 + 61 = 79°
omgblahyolo

Answer:

∠a = x

∠b = 3x + 29

∠c = x + 61

x + 3x + 29 + x + 61 = 180

5x = 180 - 29 - 61

5x = 90

x = 90/5

x = 18°  ← ∠a

∠b = 3x + 29 = 3*18 + 29 = 83°

∠c = x + 61 = 18 + 61 = 79°

Step-by-step explanation:

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