Respuesta :
You can rearrange f(x) as:
f(x) = 3(x^2 + 3x) + 12 = 3(x+1.5)^2 +5.25
So you can see the vertex is at (0,5.25) when x = -1.5
The axis of symmetry then lies in x = -1.5
f(x) = 3(x^2 + 3x) + 12 = 3(x+1.5)^2 +5.25
So you can see the vertex is at (0,5.25) when x = -1.5
The axis of symmetry then lies in x = -1.5
Answer with explanation:
Equation of the Parabola is
[tex]f(x)= y=3x^2+9x+12\\\\y=3[x^2+3 x+4]\\\\y=3[(x+\frac{3}{2})^2+4-(\frac{3}{2})^2]\\\\y=3[(x+\frac{3}{2})^2+(\frac{\sqrt 7}{2})^2]\\\\y-\frac{21}{4}=3[(x+\frac{3}{2})^2][/tex]
Vertex of the parabola can be obtained by
[tex]x+\frac{3}{2}=0\\\\ x=\frac{-3}{2}\\\\ y-\frac{21}{4}=0\\\\y=\frac{21}{4}\\\\ Vertex(\frac{-3}{2},\frac{21}{4})[/tex]
Axis is that line of parabola which divides the parabola into two equal halves.
[tex]x+\frac{3}{2}=0\\\\x=-\frac{3}{2}[/tex]
