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When looking at a rational function f of x equals the quantity x plus three times the quantity x minus two times the quantity x plus five all divided by the quantity x minus three times the quantity x plus two times the quantity x minus 5, Charles and Bobby have two different thoughts. Charles says that the function is defined at x = –2, x = 3, and x = 5. Bobby says that the function is undefined at those x values. Who is correct? Justify your reasoning.

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apologiabiology
that is confusing but I will try to make sense of it


[tex]f(x)= \frac{(x+3)(x-2)(x+5)}{(x-3)(x+2)(x-5)} [/tex] is what I think you aer getting

it is undefined in values of x where you divide by 0

set denomenator to 0 and solve
0=(x-3)(x+2)(x-5)

0=x-3
3=x

0=x+2
-2=x

0=x-5
5=x

undefined at x=-2, x=3 and x=5


bobby is correct because of math and it is undefined when you divide by 0

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