Respuesta :

mreijepatmat
a₁ = 10
r = 1/5

Sum of GP = a₁(1-rⁿ)/(1-r), where a₁ = 1st term; n= rank and r = common ratio

Sum = 10[1-(1/5)⁵] /(1-1/5)
Sum = 10(1-1/3250)/(4/5)
Sum = 1562/125
JeanaShupp

Answer: 12.496

Step-by-step explanation:

The formula to find the sum of geometric progression is given by :-

[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]

Given : The first term : [tex]a_1=10[/tex]

Common ratio = [tex]r=\dfrac{1}{5}=0.2[/tex]

Then , the sum of first five terms of a geometric series is given by :-

[tex]S_5=\dfrac{10(1-(0.2)^5)}{1-0.2}=12.496[/tex]

Hence, the sum of the first five terms of given geometric series =12.496

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