Given:
Initial mass, m₀ = 23 g
Decay constant, k = 0.13
Exponential decay obeys the equation
[tex]m(t)=m_{0} e^{-kt}[/tex]
where t = time, days
For half life, the mass is m = m₀/2.
Therefore
[tex]e^{-0.13t} = \frac{1}{2} \\ -0.13t = ln(0.5)\\t= \frac{ln(0.5)}{-0.13} =5.33[/tex]
Answer: The half life is 5.33 days
