What are the x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4?

To solve this problem, we are given the formulas for our new x and y. To use this formula, we must first establish our points 1 and 2. Since the problem specifically directed the point E which partitions the line segment “from J to K”, therefore
point 1 = point J = (x1, y1)
point 2 = point K = (x2, y2)
The variables m and n indicates the portion of partition segment JE and EK that takes up from the original segment. Since the ratio is 1:4, then:
JE = m = 1
EK = n = 4
Therefore calculating for x and y using the given formulas:
x = [1 / (1 + 4)] (25 – (-15)) + (-15)
x = -7
y = [1 / (1 + 4)] (15 – (-5)) + (-5)
y = -1
Therefore the coordinates of point E is (-7, -1)
The x- and y- coordinates of point E (-7,-1)
In the coordinates of the two-dimensional plane (xy) there is a position vector.
Two dimensions because the coordinates are only x and y, three dimensions if the coordinates are x, y, and z.
If there is a point P then
You can write P as:
P = xi + yi
where i denotes the unit vector in the x and y directions
While the size of the vector:
[tex]\displaystyle P = \sqrt{x^2+y^2}[/tex]
and its direction
[tex]\displaystyle \theta=arc\:tan\:\frac{y}{x}[/tex]
If a point C divides the line segment AB by the ratio m: n, then the coordinates of point C can be formulated:
[tex]\displaystyle \vec{C}=\frac{m\vec{b}+n\vec{a}}{m+n}[/tex]
Coordinate x :
[tex]\displaystyle x=\frac{m.x_2+n.x_1}{m+n}[/tex]
Coordinate y :
[tex]\displaystyle y=\frac{m.y_2+n.y_1}{m+n}[/tex]
line segment from J to K into a ratio of 1:4, then m = 1 and n = 4
(x1,y1) from point J= (-15,-5)
(x2,y2) from point K= (25,15)
So coordinates of point E :
Coordinate x :
[tex]\displaystyle x=\frac{1.25+4.-15}{5}[/tex]
x = -7
Coordinate y :
[tex]\displaystyle y=\frac{1.15+4.-5}{5}[/tex]
y = -1
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Keywords: line segment, vector, two-dimensional coordinates , x,y, partitions