You have to look up in your Z score table.
P( 0.6≤ z≤ 2012) is the probability or area (of the bell shaped curve) between the value of z = 2.212 & z = 0.6.
To that end for z₁ = 2.12 you find an area = 0.9830 and
for z₂ = 0.6 you find an area = 0.7257
Subtract those values z₁ - z₂ = 0.9830 - 0.7257 = 0.2573
and P( 0.6≤ z≤ 2012) = 0.2573 (0r 25.73%)
