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A mixture of three noble gases has a total pressure of 1.25 atm the individual pressures exerted by neon and argon are 0.68 atm and 0.38 atm respectively.what is the partial pressure of the third gas ,helium

Respuesta :

daniel987
P = P1 + P2 + P3
1.25 = 0.68 + 0.38 + P3
P3 = 1.25 - 0.68 +0.38
P3 = 0.19

Or

Add the both known pressures 0.68 + 0.38 = 1.06
Know subtract the two gas pressures from the total pressure: 1.25 - 1.06 = 0.19atm
Hope that helps 

Answer: 0.19 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

[tex]p_{total}=p_1+p_2+p_3[/tex]

Given : [tex]p_{total}[/tex] = 1.25 atm

[tex]p_{Ne}[/tex] = 0.68 atm

[tex]p_{Ar}[/tex] = 0.38 atm

[tex]p_{He}[/tex] = ?

[tex]p_{total}=p_{Ne}+p_{Ar}+p_{He}[/tex]

Putting in the values:

[tex]1.25=0.68+0.38+p_{He}[/tex]

[tex]p_{He}=0.19atm[/tex]

Thus partial pressure of the third gas helium is 0.19 atm

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