contestada

Suppose you have a box with 3 blue marbles, 2 red marbles, and 4 yellow marbles. You are going to pull out one marble, record its color, put it back in the box and draw another marble. What is the probability of pulling out a red marble followed by a blue marble? Be sure to reduce your answers. a. 6/81 = 2/27
b. 6/18 = 1/3
c. 5/9
d. 5/18

Respuesta :

musiclover10045

red = 2/9

blue = 3/9 = 1/3

 multiply together

2/9 x 1/3 = 2/27 so answer is a

MrRoyal

Probabilities are used to determine the chances of events

The probability of pulling out a red marble followed by a blue marble is 2/27

The given parameters are:

Blue = 3

Red = 2

Yellow = 4

The total number of marbles is 9 i.e. 3 + 2 + 4

The probability of selecting a red marble is:

[tex]P(Red) = \frac 29[/tex]

The probability of selecting a blue marble is:

[tex]P(Blue) = \frac 39[/tex]

The probability of selecting both is:

[tex]P(Both) = P(Red) * P(Blue)[/tex]

This gives

[tex]P(Both) = \frac29 \times \frac 39[/tex]

Multiply

[tex]P(Both) = \frac{6}{81}[/tex]

Reduce fraction

[tex]P(Both) = \frac{2}{27}[/tex]

Hence, the probability is 2/27

Read more about probability at:

https://brainly.com/question/25870256

Otras preguntas