Answer:
86.9%
Explanation:
Moles of CuCl₂ = mass of CuCl₂/molar mass of CuCl₂= 15g / 135.45 g/ml = 0.11 moles
Moles of NaNO₃ = mass of NaNO₃/molar mass of NaNO₃ = 20 g / 84.9947 g/ml = 0.2353 moles
CuCl₂ is the limiting agent as it has lowest number of moles.
CuCl₂ will dictate the yield of NaCl.
From the balanced equation,
1 mole of CuCl₂ = 2 moles of NaCl
0.11 moles of CuCl₂ = 0.22 moles of NaCl
Mass of NaCl = moles of NaCl x molar mass of NaCl = 0.22 mol x 58.44 g/mol = 12.8568 g
Percent yield = actual yield/ theoretical yield x 100
Percent yield is the ratio of the actual yield to the theoretical yield
Given,
Actual yield NaCl = 11.3 g
Theoretical yield NaCl = 12.8568 g ~ 13 g
Percent yield = 11.3 g / 13 g = 86.9%
