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An engineer is surveying a building with a device that is 5 feet above the ground. He is 50 feet from the building and is looking with an angle of elevation of 50°. How tall is the building?

Respuesta :

1. Check the sketch of the problem.

2. In right triangle DCE,

 [tex]tan50= \frac{EC}{DC}= \frac{x}{50} [/tex]

tan 50 can be found to be 1.19 using a scientific calculator or other software.

[tex]1.19=\frac{x}{50}[/tex]

x=1.19*50=59.5 (feet)

3. The height of the building is 59.5+5=64.5 (feet)

Answer: 64.5 (feet)
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