Answer:
Step-by-step explanation:
Ok since no one decided to answer my question, here is the answer
from aops:
We note that
[tex]$5400 = 2^3 3^3 5^2$. The square-free divisors of this number therefore have the form $2^a 3^b 5^c$ where each of $a$, $b$, $c$ is zero or a one. The sum of all such integers is\[ (1+2)(1+3)(1+5). \](The proof of this fact is analogous to our proof for the formula for the sum of the divisors of a positive integer.) Therefore our answer is $3 \cdot 4 \cdot 6 = \boxed{72}$.[/tex]
as you can see, the "verified answer" is complete garbage.
