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Consider the nuclear equation below.

What is the nuclide symbol of X?

A) 231/94 Pu
B) 235/90 Th
C) 239/94 Pu
D) 231/90 Th

Consider the nuclear equation below What is the nuclide symbol of X A 23194 Pu B 23590 Th C 23994 Pu D 23190 Th class=

Respuesta :

²³⁵₉₂U → ²³¹₉₀Th + ⁴₂He

D) ²³¹₉₀Th 

Answer;

D) ²³¹₉₀Th

Explanation;

²³⁵₉₂U → ²³¹₉₀Th + ⁴₂He

This is known as alpha decay

Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and thereby transforms or 'decays' into a different atomic nucleus, with a mass number that is reduced by four and an atomic number that is reduced by two.

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