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which equation can be solved to find one of the missing side lengths in the triangle? cos(60o) =
cos(60o) =
cos(60o) =
cos(60o) =

which equation can be solved to find one of the missing side lengths in the triangle cos60o cos60o cos60o cos60o class=

Respuesta :

mreijepatmat
If we want to calculate a, then cos(60°) = a/12, but we know that cos(60°) = 1/2,
then 1/2 = a/12 and a = 6

If we want to calculate b, then sin(60°) = b/12, but we know that cos(60°) = (√3)/2
then (√3)/2 = b/12 and b = 6√3

The correct statement is that the other sides of the triangles are 6 and 10.392 units.

What is trigonometry?

Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.

Right angle triangle

It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function.

Given

AB = 12 units and angle B is 60.

To find

The other sides of the triangle.

How do find the other sides?

Let, BC is a base and AC is a perpendicular, then cosine will be

[tex]\begin{aligned} \rm cos \theta &= \rm \dfrac{Base}{Hypotenuse}\\\\\rm cos\ 60 &= \dfrac{BC}{12}\\\\\rm BC &= 6\\\end{aligned}[/tex]

Similarly for sine,

[tex]\begin{aligned} \rm sin\ \theta &= \rm \dfrac{Perpendicular}{Hypotenuse}\\\\\rm sin \ 60 &= \dfrac{AC}{12}\\\\\rm AC &= 10.392\\\end{aligned}[/tex]

Thus the other sides of triangles are 6 and 10.392 units.

More about the trigonometry link is given below.

https://brainly.com/question/13710437

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