Respuesta :

mjankiewicz
f(x) = y = 0
[tex]x^2+6x-17=0 \\\\ (x^2+6x+9)-9-17=0 \\\\ (x+3)^2=26 \\\\ \sqrt{(x+3)^2}=\sqrt{26} \\\\ x+3=\sqrt{26} \ or \ x+3=-\sqrt{26} \\\\ x=\sqrt{26}-3 \ or \ x = -\sqrt{26}-3[/tex]

The x-intercepts of the parabola are [tex]\sqrt{26}-3 \ and \ -\sqrt{26}-3[/tex]

Answer:

X intercept are (-8.09,0) and (2.09,0)

Y intercept (o,-17)

Step-by-step explanation: