Respuesta :
v=(4/3)pir^3
d/2=r
given
d=12
d/2=12/2=6
v=(4/3)pi6^3
v=(4/3)pi216
v=288pi
v=904.32 cubic inches
2nd question
we will use
x=radius larger
y=radius smaler
area=pir²
if bigger is 36 times smaller then
36 times smaller=bigger
36pix²=piy²
divide both sides by pi
36x²=y²
sqrt both sides
6x=y
the larger circle is 6 times the radius of the smaller circle
d/2=r
given
d=12
d/2=12/2=6
v=(4/3)pi6^3
v=(4/3)pi216
v=288pi
v=904.32 cubic inches
2nd question
we will use
x=radius larger
y=radius smaler
area=pir²
if bigger is 36 times smaller then
36 times smaller=bigger
36pix²=piy²
divide both sides by pi
36x²=y²
sqrt both sides
6x=y
the larger circle is 6 times the radius of the smaller circle