How much will $600 amount to be if it is invested at 10% interest compounded semiannually (two times a year) for 4 years? A. $886.47 B. $952.40 C. $1063.20 D. $1168.17
A = P(1 + (r/n)^(nt) A = amount after given period of time P = principle r = rate (change to decimal) n = number of times compounded per year t = number of years A = 600(1 + (.10/2))^(2*4) A = $866.47 LETTER A is the answer
