Answer : The energy required will be, 85200 J
Solution :
Formula used :
[tex]Q=m\times c\times \Delta T[/tex]
where,
Q = heat required = ?
m = mass of graphite = 750 g
c = specific heat capacity of graphite = [tex]0.71J/g^oC[/tex]
[tex]\Delta T=\text{Change in temperature}[/tex] = [tex]160^oC[/tex]
Now put all the given values in the above formula, we get heat required.
[tex]Q=(750g)\times (0.71J/g^oC)\times (160^oC)=85200J[/tex]
Therefore, the energy required will be, 85200 J
