Answer:
[tex]-1.7\cdot 10^6 kg m/s[/tex]
Explanation:
The impulse is equal to the product between the force (F) and the time of impact ([tex]\Delta t[/tex]):
[tex]I=F \Delta t[/tex]
However, the impulse is also equal to the change in momementum of the spacecraft:
[tex]I = \Delta p= m (v_f - v_i)[/tex]
where
[tex]m=11.5 \cdot 10^4 kg[/tex] is the mass of the spacecraft
[tex]v_f = 1.2 m/s[/tex] is the final velocity
[tex]v_i = 16 m/s[/tex] is the initial velocity
Substituting these numbers into the formula, we find
[tex]I=(11.5\cdot 10^4 kg)(1.2 m/s-16 m/s)=-1.7\cdot 10^6 kg m/s[/tex]
where the negative sign simply means that the impulse is in the opposite direction to the motion of the spacecraft (in fact, it makes it slowing down).
