I will solve your system by substitution.x−5y=0;2x−3y=7Solve x−5y=0 for x:x−5y+5y=0+5y (Add 5y to both sides)x=5ySubstitute 5y for x in 2x−3y=7:2x−3y=725y−3y=77y=7 (Simplify both sides of the equation)7y7=77 (Divide both sides by 7)y=1Step: Substitute 1 for y in x=5y:x=5yx=(5)(1)x=5(Simplify both sides of the equation)
Your Answer:5 is the value of X and Y is the value of 1
