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A balloon contains 2500 ml of helium gas at 75 degrees Celsius. What is the final volume in millimeters of gas when the temperature changes to each of the following, if n and p do not change?

Respuesta :

itsmw201822
I believe the answer is 20 degrees Celsius 
Eduard22sly

Given the data from the question, the final volume of the gas is

A. 2356.3 mL

B. 4885.1 mL

A. How to determine the final volume

  • Initial volume (V₁) = 2500 mL
  • Initial temperature (T₁) = 75 °C = 75 + 273 = 348 K
  • Pressure = Constant
  • Final temperature (T₂) = 55 °C = 55 + 273 = 328 K
  • Final Volume (V₂) =?

The final volume of the gas can be obtained by using the Charles' law equation as illustrated below:

V₁ / T₁ = V₂ / T₂

2500 / 348 = V₂ / 328

Cross multiply

348 × V₂ = 2500 × 328

Divide both side by 348

V₂ = (2500 × 328) / 348

V₂ = 2356.3 mL

B. How to determine the final volume

  • Initial volume (V₁) = 2500 mL
  • Initial temperature (T₁) = 75 °C = 75 + 273 = 348 K
  • Pressure = Constant
  • Final temperature (T₂) = 680 K
  • Final Volume (V₂) =?

The final volume of the gas can be obtained by using the Charles' law equation as illustrated below:

V₁ / T₁ = V₂ / T₂

2500 / 348 = V₂ / 680

Cross multiply

348 × V₂ = 2500 × 680

Divide both side by 348

V₂ = (2500 × 680) / 348

V₂ = 4885.1 mL

Complete question

A balloon contains 2500 mL of helium gas at 75 °C. What is the final volume, in milliliters, of the gas when the temperature changes to each of the following, if pressure and amount of gas do not change? а. 55 °C b. 680. K

Learn more about gas laws:

https://brainly.com/question/6844441

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