Respuesta :
times t hours and (t+2) hours)
d1 = 50 t
d2 = 40(t+2)
50 t = 10 + 40(t+2)
10 t = 90
t = 9
d1 = 50 t
d2 = 40(t+2)
50 t = 10 + 40(t+2)
10 t = 90
t = 9
The first car traveled for 9 hours
- Let the distance of the cars be d1 and d2
If the second car traveled 2 hours longer at a speed of 40mph, then;
- t2 = t+2 hours
Get their distances
d1 = 50 t
d2 = 40(t+2)
Equate the distances
50 t = 10 + 40(t+2)
50t - 40t = 90
10t = 90
t = 9
Hence the first car traveled for 9 hours
Learn more on speed here: https://brainly.com/question/10113134