One car went 10 miles farther when traveling at 50 mph than a second car that traveled 2 hours longer at a speed of 40 mph. How long did the first car travel?

Respuesta :

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times t hours and (t+2) hours) 
d1 = 50 t 
d2 = 40(t+2) 

50 t = 10 + 40(t+2) 

10 t = 90 

t = 9

The first car traveled for 9 hours

  • Let the distance of the cars be d1 and d2

If the second car traveled 2 hours longer at a speed of 40mph, then;

  • t2 = t+2 hours

Get their distances

d1 = 50 t  

d2 = 40(t+2)

Equate the distances

50 t = 10 + 40(t+2)  

50t - 40t = 90

10t = 90

t = 9

Hence the first car traveled for 9 hours

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