Answer:
The equation of circle with Center (-1, 4), radius = √3 is [tex](x+1)^2+(y-4)^2=3[/tex]
Step-by-step explanation:
Given : Center (-1, 4), radius = √3
We have to find the equation of circle with Center (-1, 4), radius = √3.
The standard equation of circle with center (h,k) and radius r is given by
[tex](x-h)^2+(y-k)^2=r^2[/tex],
Given Center (-1, 4), radius = √3
Subsitute, h = -1 , k = 4 and r = √3
We have,
[tex](x-(-1))^2+(y-4)^2=(\sqrt{3})^2[/tex]
Simplify, we have,
[tex](x+1)^2+(y-4)^2=3[/tex]
Thus, The equation of circle with Center (-1, 4), radius = √3 is [tex](x+1)^2+(y-4)^2=3[/tex]
