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Please HELP!!! I'll mark Brainiest!!

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

y-2= 7/3(x+5) ; (-5, 2)

A: y+2= -3/7 (x-5)
B: y-5= -3/7(x+2)
C: y-2= -3/7(x+5)
D: y+2= 3/7(x-5)

A:

Respuesta :

apologiabiology
equation of a line that passses through (x1,y1) and has a slope of m is
y-y1=m(x-x1)

perpendicular lines have slopes that mulitply to get -1
given
y-2=7/3(x+5)
slope is 7/3

perpendicular
7/3 times slope=-1
times 3/7 both sides
slope=-3/7

given point is (-5,2)

y-2=-3/7(x-(-5))
y-2=-3/7(x+5)

C is answer

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