Respuesta :
A mole of anything contains 6.022x10^23 items. so we need to divide this
1.3 x 10^25 / 6.022 x 10^23 = 21.59 moles
1.3 x 10^25 / 6.022 x 10^23 = 21.59 moles
Answer : The moles of [tex]CO_2[/tex] in the flask are, 21.58 moles.
Solution :
As we are given the molecules of [tex]CO_2[/tex] in the flask are =[tex]1.3\times 10^{25}[/tex]. Now we have to calculate the moles of [tex]CO_2[/tex] in the flask.
As, [tex]6.022\times 10^{23}[/tex] molecules of [tex]CO_2[/tex] present in 1 mole of [tex]CO_2[/tex].
So, [tex]1.3\times 10^{25}[/tex] molecules of [tex]CO_2[/tex] present in [tex]\frac{1.3\times 10^{25}}{6.022\times 10^{23}}=21.58[/tex] moles of [tex]CO_2[/tex].
Therefore, the moles of [tex]CO_2[/tex] in the flask are, 21.58 moles.