Respuesta :
we know that
area of the circle is equal to
[tex]A=pi* r^{2} [/tex]
solve for r
[tex]r= \sqrt{ \frac{A}{pi}} [/tex]
for A=[tex]60 cm^{2} [/tex]
[tex]r= \sqrt{ \frac{60}{pi}} cm[/tex]
we know that
[tex] \sqrt{60} = \sqrt{ 2^{4}*3*5} \\ =2 \sqrt{15} [/tex]
so
[tex]\sqrt{ \frac{60}{pi}}=2 \sqrt{ \frac{15}{pi}} [/tex]
[tex]2 \sqrt{ \frac{15}{pi}}=2 \frac{ \sqrt{15}}{ \sqrt{pi}} * \frac{ \sqrt{pi}}{ \sqrt{pi}} [/tex]
[tex]=2 \frac{ \sqrt{15pi}}{pi} cm [/tex]
the answer is
[tex]2 \frac{ \sqrt{15pi}}{pi} cm[/tex]
area of the circle is equal to
[tex]A=pi* r^{2} [/tex]
solve for r
[tex]r= \sqrt{ \frac{A}{pi}} [/tex]
for A=[tex]60 cm^{2} [/tex]
[tex]r= \sqrt{ \frac{60}{pi}} cm[/tex]
we know that
[tex] \sqrt{60} = \sqrt{ 2^{4}*3*5} \\ =2 \sqrt{15} [/tex]
so
[tex]\sqrt{ \frac{60}{pi}}=2 \sqrt{ \frac{15}{pi}} [/tex]
[tex]2 \sqrt{ \frac{15}{pi}}=2 \frac{ \sqrt{15}}{ \sqrt{pi}} * \frac{ \sqrt{pi}}{ \sqrt{pi}} [/tex]
[tex]=2 \frac{ \sqrt{15pi}}{pi} cm [/tex]
the answer is
[tex]2 \frac{ \sqrt{15pi}}{pi} cm[/tex]
Another way to represent the radius is [tex]\dfrac{2\sqrt{15}}{\pi}[/tex].
The radius of a circle with an area of 60 square centimeters is represented by the expression √60/π centimeters.
We need to express the radius in another way from the given options.
Options are as follow:
A. 2√15π
B. 4√5π
C. 2√15π/π
D. 4√5π/π
Now, take the given value and solve it according to our options.
[tex]\begin{aligned}r&=\dfrac{\sqrt{60}}{\pi}\\&=\dfrac{\sqrt{2 \times 2 \times 15}}{\pi}\\&=\dfrac{2\sqrt{15}}{\pi} \end{aligned}[/tex]
Hence, another way to represent the radius is [tex]\dfrac{2\sqrt{15}}{\pi}[/tex].
To know more about the radius, please refer to the link:
https://brainly.com/question/20188113