If the function is h(t)=-2[tex](t+5)^{2}[/tex]+4 then h(-8) is equal to -14.
A function is relationship between two or more variables expressed in equal to form. In the function each value of x should have corresponding value of y. The value of x is domain of the function and the value of function is called codomain or range of function.
We have been given the function h(t)=-2[tex](t+5)^{2}[/tex]+4 and we have to find the value of function at t=-8.So to find the value we have to just put t=-8 in the given function.
h(t)=-2[tex](t+5^{2} +4[/tex]
h(-8)=-2[tex](-8+5)^{2}[/tex]+4
=-2*[tex]-3^{2}[/tex]+4
=-2*9+4
=-18+4
=-14
Hence if function is h(t)=[tex]-2(t+5)^{2} +4[/tex] then the value of h(-8)=-14.
Learn more about function at https://brainly.com/question/10439235
#SPJ2
