Let the equations be f(x) and g(x) respectively.
Now, equation f(x) has an equation solved for y.
Thus, we know a value for y.
We can then substitute that into the second equation.
[tex]f(x) = y = 2x - 3[/tex]
[tex]g(x): 2x - 2y = 2[/tex]
Substitute f(x) for wherever y is in g(x):
[tex]g(x): 2x - 2(2x - 3) = 2[/tex]
[tex]2x - 4x + 6 = 2[/tex]
[tex]-2x = -4; x = 2[/tex]
Now, substitute x = 2 into f(x) to find the value for y.
[tex]y = 2(2) - 3[/tex]
[tex]y = 4 - 3 = 1[/tex]
[tex]\therefore x = 2, y = 1[/tex]
